Find the square. Simplify your answer. (2f + 1)^2 ______

Identify binomial form: We need to find the square of the binomial (2f + 1). This is in the form of (a + b)^2, which can be expanded using the formula (a + b)^2 = a^2 + 2ab + b^2.Determine values of a and b: Identify the values of a and b in the binomial (2f + 1). Here, a = 2f and b = 1.Apply binomial formula: Apply the square of a binomial formula to expand (2f + 1)^2. (2f + 1)^2 = (2f)^2 + 2(2f)(1) + 1^2Simplify each term: Simplify each term in the expansion. (2f)^2 = 4f^2 2(2f)(1) = 4f 1^2 = 1 So, (2f + 1)^2 = 4f^2 + 4f + 1

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Find the square. Simplify your answer. $\newline$ $(2f + 1)^2$

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Algebra 1

Multiply two binomials: special cases

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Q. Find the square. Simplify your answer.

\newline

(2f + 1)^2

Identify binomial form: We need to find the square of the binomial $(2f + 1)$ . This is in the form of $(a + b)^2$ , which can be expanded using the formula $(a + b)^2 = a^2 + 2ab + b^2$ .
Determine values of $a$ and $b$ : Identify the values of $a$ and $b$ in the binomial $(2f + 1)$ . Here, $a = 2f$ and $b = 1$ .
Apply binomial formula: Apply the square of a binomial formula to expand $(2f + 1)^2$ . $(2f + 1)^2 = (2f)^2 + 2(2f)(1) + 1^2$
Simplify each term: Simplify each term in the expansion. $\newline$ $(2f)^2 = 4f^2$ $\newline$ $2(2f)(1) = 4f$ $\newline$ $1^2 = 1$ $\newline$ So, $(2f + 1)^2 = 4f^2 + 4f + 1$