Find the solution of the system of equations. {:[-x+6y=23],[-8x-3y=31]:} (◻,◻)

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Find the solution of the system of equations.  {:[-x+6y=23],[-8x-3y=31]:}  (◻,◻)

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Write Equations: Write down the system of equations to be solved. We have the following system of equations: 1) -x + 6y = 23 2) -8x - 3y = 31 We will use the method of substitution or elimination to find the values of x and y that satisfy both equations.Choose Solution Method: Decide which method to use for solving the system. We can use either substitution or elimination. In this case, we will use the elimination method because it seems straightforward to eliminate x by multiplying the first equation by 8 and adding it to the second equation.Multiply First Equation: Multiply the first equation by 8 to prepare for elimination. Multiplying the first equation by 8 gives us: 8(-x + 6y) = 8(23) Which simplifies to: -8x + 48y = 184Add Equations for Elimination: Add the new equation to the second equation to eliminate x. We add -8x + 48y = 184 (from Step 3) to -8x - 3y = 31 (the second original equation): (-8x + 48y) + (-8x - 3y) = 184 + 31 This simplifies to: -16x + 45y = 215

Find the solution of the system of equations. $\newline$ $\begin{aligned} -x+6 y & =23 \\ -8 x-3 y & =31 \end{aligned}$ $\newline$ $(\square, \square)$

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Find the solution of the system of equations.\newline−x+6yamp;=23−8x−3yamp;=31 \begin{aligned} -x+6 y &amp; =23 \\ -8 x-3 y &amp; =31 \end{aligned} −x+6y−8x−3y​amp;=23amp;=31​\newline(□,□) (\square, \square) (□,□)

Find the solution of the system of equations. $\newline$ $\begin{aligned} -x+6 y & =23 \\ -8 x-3 y & =31 \end{aligned}$ $\newline$ $(\square, \square)$