Find the solution of the system of equations. {:[x-4y=6],[x-6y=12]:}\(_________,________)

Eliminate x: Subtract the second equation from the first to eliminate x. (x - 4y) - (x - 6y) = 6 - 12Simplify subtraction: Simplify the subtraction. x - x - 4y + 6y = 6 - 12Combine like terms: Combine like terms. 2y = -6Solve for y: Divide both sides by 2 to solve for y. y = -6 / 2Calculate y value: Calculate the value of y. y = -3Solve for x: Substitute y = -3 into the first equation to solve for x. x - 4(-3) = 6Multiply and simplify: Multiply 4 by -3. x + 12 = 6Calculate x value: Subtract 12 from both sides to solve for x. x = 6 - 12Calculate the value of x. x = -6

Home

Math Problems

Grade 8

Write an equation word problem

Full solution

Q. Find the solution of the system of equations.

\newline

\begin{array}{l} x-4 y=6 \\ x-6 y=12 \end{array}

\newline

\newline

(_________,________)

Eliminate x: Subtract the second equation from the first to eliminate x. $\newline$ $(x - 4y) - (x - 6y) = 6 - 12$
Simplify subtraction: Simplify the subtraction. $x - x - 4y + 6y = 6 - 12$
Combine like terms: Combine like terms. $2y = -6$
Solve for y: Divide both sides by $2$ to solve for y. $y = \frac{-6}{2}$
Calculate y value: Calculate the value of y. $\newline$ $y = -3$
Solve for x: Substitute $y = -3$ into the first equation to solve for x. $x - 4(-3) = 6$
Multiply and simplify: Multiply $4$ by $-3$ . $x + 12 = 6$
Calculate x value: Subtract $12$ from both sides to solve for $x$ . $\newline$ $x = 6 - 12$
Calculate $x$ value: Subtract $12$ from both sides to solve for $x$ .
$x = 6 - 12$ Calculate the value of $x$ .
$x = -6$