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![Find the solution of the system of equations.
{:[x-3y=35],[6x+6y=-30]:}](https://externalquestionsimg-a4fuc2b6e0gtdqge.z01.azurefd.net/external-question-images/images/images/dm/Grade-8/Systems%20of%20Equations/Elimination%20%28Level%202%29/Q-45.png)
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Q. Find the solution of the system of equations.
- Write Equations: Write down the system of equations to be solved.We have the following system of equations:) )
- Simplify Second Equation: Simplify the second equation by dividing all terms by to make it easier to work with.Dividing the second equation by gives us:
- New System of Equations: Now we have a new system of equations:) ) We can solve this system using the method of substitution or elimination. In this case, we will use the elimination method by subtracting the second equation from the first.Subtracting the second equation from the first gives us:This simplifies to:
- Solve for y: Solve for y by dividing both sides of the equation by -4＂).\(\newline\$-4y / -4 = 40 / -4\)\(\newline\)This gives us:\(\newline\)\(y = -10\)
- Substitute for \(x\): Substitute the value of \(y\) back into one of the original equations to solve for \(x\). We can use the second equation \(x + y = -5\).\(\newline\)Substituting \(y = -10\) into the equation gives us:\(\newline\)\(x - 10 = -5\)
- Final Solution: Solve for \(x\) by adding \(10\) to both sides of the equation.\(\newline\)\(x - 10 + 10 = -5 + 10\)\(\newline\)This gives us:\(\newline\)\(x = 5\)
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