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Find the solution of the system of equations.

{:[x+3y=13],[-x+2y=12]:}

(_________,________)

Find the solution of the system of equations.\newlinex+3yamp;=13x+2yamp;=12 \begin{aligned} x+3 y & =13 \\ -x+2 y & =12 \end{aligned} \newline\newline(_________,________)

Full solution

Q. Find the solution of the system of equations.\newlinex+3y=13x+2y=12 \begin{aligned} x+3 y & =13 \\ -x+2 y & =12 \end{aligned} \newline\newline(_________,________)
  1. Add Equations Together: Add the two equations together to eliminate xx.(x+3y)+(x+2y)=13+12(x + 3y) + (-x + 2y) = 13 + 123y+2y=253y + 2y = 255y=255y = 25
  2. Divide to Solve for y: Divide both sides by 55 to solve for yy.5y5=255\frac{5y}{5} = \frac{25}{5}y=5y = 5
  3. Substitute yy into First Equation: Substitute y=5y = 5 into the first equation to solve for xx.x+3(5)=13x + 3(5) = 13x+15=13x + 15 = 13
  4. Subtract to Solve for x: Subtract 1515 from both sides to solve for xx.\newlinex+1515=1315x + 15 - 15 = 13 - 15\newlinex=2x = -2