Find the solution of the system of equations. {:[6x-y=-30],[-3x+6y=-18]:} (◻,◻)

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Find the solution of the system of equations.  {:[6x-y=-30],[-3x+6y=-18]:}  (◻,◻)

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Write Equations: Write down the system of equations to be solved. We have the system: 6x - y = -30 -3x + 6y = -18 We will use the method of substitution or elimination to solve this system.Choose Method: Decide on a method to solve the system. We can use the elimination method by multiplying the second equation by 2 to make the coefficients of x the same in both equations.Multiply Second Equation: Multiply the second equation by 2. 2(-3x + 6y) = 2(-18) This gives us: -6x + 12y = -36 Now we have the system: 6x - y = -30 -6x + 12y = -36Add Equations: Add the two equations together to eliminate x. (6x - y) + (-6x + 12y) = -30 + (-36) This simplifies to: 11y = -66Solve for y: Solve for y. Divide both sides by 11 to find the value of y. y = -66 / 11 y = -6Substitute for x: Substitute the value of y into one of the original equations to solve for x. We can use the first equation: 6x - y = -30 Substitute y = -6: 6x - (-6) = -30 6x + 6 = -30Solve for x: Solve for x. Subtract 6 from both sides to isolate x: 6x = -30 - 6 6x = -36 Divide both sides by 6: x = -36 / 6 x = -6

Find the solution of the system of equations. $\newline$ $\begin{array}{r} 6 x-y=-30 \\ -3 x+6 y=-18 \end{array}$ $\newline$ $(\square, \square)$

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Find the solution of the system of equations.\newline6x−y=−30−3x+6y=−18 \begin{array}{r} 6 x-y=-30 \\ -3 x+6 y=-18 \end{array} 6x−y=−30−3x+6y=−18​\newline(□,□) (\square, \square) (□,□)

Find the solution of the system of equations. $\newline$ $\begin{array}{r} 6 x-y=-30 \\ -3 x+6 y=-18 \end{array}$ $\newline$ $(\square, \square)$