Find the solution of the system of equations. {:[6x-y=-30],[-3x+6y=-18]:}

Question

Find the solution of the system of equations.  {:[6x-y=-30],[-3x+6y=-18]:}

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Write Equations: Write down the system of equations to be solved. We have the following system of equations: 6x - y = -30 -3x + 6y = -18Multiply First Equation: Multiply the first equation by 6 to prepare for elimination. Multiplying the first equation by 6 gives us: (6x - y) * 6 = -30 * 6 Which simplifies to: 36x - 6y = -180Add Equations: Add the modified first equation to the second equation to eliminate y. Adding the equations (36x - 6y) + (-3x + 6y) gives us: (36x - 6y) + (-3x + 6y) = -180 + (-18) Which simplifies to: 33x = -198Solve for x: Solve for x. Dividing both sides of the equation by 33 gives us: x = -198 / 33 Which simplifies to: x = -6Substitute and Solve for y: Substitute the value of x back into one of the original equations to solve for y. Using the first equation 6x - y = -30, we substitute x = -6: 6(-6) - y = -30 Which simplifies to: -36 - y = -30Final Solution: Solve for y. Adding 36 to both sides of the equation gives us: -36 + 36 - y = -30 + 36 Which simplifies to: -y = 6 Multiplying both sides by -1 gives us: y = -6

Find the solution of the system of equations. $\newline$ $\begin{array}{r} 6 x-y=-30 \\ -3 x+6 y=-18 \end{array}$

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Find the solution of the system of equations.\newline6x−y=−30−3x+6y=−18 \begin{array}{r} 6 x-y=-30 \\ -3 x+6 y=-18 \end{array} 6x−y=−30−3x+6y=−18​

Find the solution of the system of equations. $\newline$ $\begin{array}{r} 6 x-y=-30 \\ -3 x+6 y=-18 \end{array}$