Find the solution of the system of equations. {:[-5x+5y=-35],[-5x+8y=-50]:}

Eliminate x: Subtract the first equation from the second to eliminate x. (-5x + 8y) - (-5x + 5y) = -50 - (-35) 8y - 5y = -50 + 35 3y = -15Solve for y: Divide both sides by 3 to solve for y. 3y / 3 = -15 / 3 y = -5Substitute y into first equation: Substitute y = -5 into the first equation to solve for x. -5x + 5(-5) = -35 -5x - 25 = -35Isolate -5x: Add 25 to both sides to isolate -5x. -5x - 25 + 25 = -35 + 25 -5x = -10Solve for x: Divide both sides by -5 to solve for x. -5x / -5 = -10 / -5 x = 2

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Q. Find the solution of the system of equations.

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\begin{array}{l} -5 x+5 y=-35 \\ -5 x+8 y=-50 \end{array}

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(_________,________)

Eliminate $x$ : Subtract the first equation from the second to eliminate $x$ .$\newline$( $-5x + 8y$ ) - ( $-5x + 5y$ ) = $-50$ - ( $-35$ )$\newline$ $8y - 5y = -50 + 35$ $\newline$ $x$ $0$
Solve for y: Divide both sides by $3$ to solve for y. $\newline$ $\frac{3y}{3} = \frac{-15}{3}$ $\newline$ $y = -5$
Substitute $y$ into first equation: Substitute $y = -5$ into the first equation to solve for $x$ .
$-5x + 5(-5) = -35$
$-5x - 25 = -35$
Isolate $-5x$ : Add $25$ to both sides to isolate $-5x$ . $\newline$ $-5x - 25 + 25 = -35 + 25$ $\newline$ $-5x = -10$
Solve for x: Divide both sides by $-5$ to solve for x. $\newline$ $-5x / -5 = -10 / -5$ $\newline$ $x = 2$