Find the solution of the system of equations. {:[4x+y=-43],[2x-8y=4]:}

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Find the solution of the system of equations.  {:[4x+y=-43],[2x-8y=4]:}

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Write Equations: Write down the system of equations to be solved. We have the following system of equations: 4x + y = -43 2x - 8y = 4Multiply to Eliminate y: Multiply the first equation by 8 to eliminate y. Multiplying the first equation by 8 gives us: 8(4x + y) = 8(-43) 32x + 8y = -344Add Equations: Add the modified first equation to the second equation to eliminate y. We now have: 32x + 8y = -344 2x - 8y = 4 Adding these two equations together gives us: (32x + 2x) + (8y - 8y) = -344 + 4 34x = -340Solve for x: Solve for x. Divide both sides of the equation by 34 to find x: 34x / 34 = -340 / 34 x = -10Substitute x for y: Substitute x back into one of the original equations to solve for y. Using the first equation 4x + y = -43, we substitute x = -10: 4(-10) + y = -43 -40 + y = -43Solve for y: Solve for y. Add 40 to both sides of the equation to isolate y: -40 + y + 40 = -43 + 40 y = -3

Find the solution of the system of equations. $\newline$ $\begin{aligned} 4 x+y & =-43 \\ 2 x-8 y & =4 \end{aligned}$

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Find the solution of the system of equations.\newline4x+yamp;=−432x−8yamp;=4 \begin{aligned} 4 x+y &amp; =-43 \\ 2 x-8 y &amp; =4 \end{aligned} 4x+y2x−8y​amp;=−43amp;=4​

Find the solution of the system of equations. $\newline$ $\begin{aligned} 4 x+y & =-43 \\ 2 x-8 y & =4 \end{aligned}$