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Find the solution of the system of equations.

{:[4x-y=15],[8x+7y=-33]:}

Find the solution of the system of equations.\newline4xyamp;=158x+7yamp;=33 \begin{aligned} 4 x-y & =15 \\ 8 x+7 y & =-33 \end{aligned}

Full solution

Q. Find the solution of the system of equations.\newline4xy=158x+7y=33 \begin{aligned} 4 x-y & =15 \\ 8 x+7 y & =-33 \end{aligned}
  1. Solve for y: Solve the first equation for y.\newlineWe can express yy in terms of xx using the first equation 4xy=154x - y = 15.\newliney=4x15y = 4x - 15
  2. Substitute in second equation: Substitute the expression for yy into the second equation.\newlineWe will replace yy in the second equation 8x+7y=338x + 7y = -33 with the expression we found in Step 11.\newline8x+7(4x15)=338x + 7(4x - 15) = -33
  3. Distribute and combine terms: Distribute and combine like terms.\newlineNow we distribute 77 into the parentheses and combine like terms.\newline8x+28x105=338x + 28x - 105 = -33\newline36x105=3336x - 105 = -33
  4. Add 105105 to isolate x: Add 105105 to both sides of the equation to isolate the term with x.\newline36x105+105=33+10536x - 105 + 105 = -33 + 105\newline36x=7236x = 72
  5. Divide to solve for x: Divide both sides by 3636 to solve for x.\newlinex=7236x = \frac{72}{36}\newlinex=2x = 2
  6. Substitute xx into yy expression: Substitute xx back into the expression for yy. Now that we have the value for xx, we can find yy by substituting xx into y=4x15y = 4x - 15. y=4(2)15y = 4(2) - 15 y=815y = 8 - 15 yy00