Find the solution of the system of equations. {:[-4x-8y=-20],[8x+3y=1]:}

Question

Find the solution of the system of equations.  {:[-4x-8y=-20],[8x+3y=1]:}

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Elimination Method: Let's start by solving the system of equations using the method of elimination or substitution. We will use elimination in this case. First, we need to make the coefficients of one of the variables the same in both equations so we can eliminate that variable. We can multiply the second equation by 4 to match the coefficient of x in the first equation. Calculation: (8x + 3y = 1) * 4 New system of equations: -4x - 8y = -20 32x + 12y = 4Adding Equations: Now, we add the two equations together to eliminate x. Calculation: (-4x - 8y) + (32x + 12y) = -20 + 4 New equation: 28y = -16Solving for y: Next, we solve for y by dividing both sides of the equation by 28. Calculation: 28y / 28 = -16 / 28 y = -16 / 28 y = -4 / 7Substitute Back: Now that we have the value of y, we can substitute it back into one of the original equations to find x. We'll use the first equation for this purpose. Substitution: -4x - 8(-4/7) = -20 Calculation: -4x + 32/7 = -20Clearing Denominators: To solve for x, we first need to get rid of the fraction by multiplying every term by 7 to clear the denominators. Calculation: 7(-4x) + 7(32/7) = 7(-20) -28x + 32 = -140Move 32: Next, we move 32 to the other side of the equation by subtracting it from both sides. Calculation: -28x = -140 - 32 -28x = -172Final Solution: Finally, we solve for x by dividing both sides of the equation by -28. Calculation: x = -172 / -28 x = 172 / 28 x = 43 / 7

Find the solution of the system of equations. $\newline$ $\begin{aligned} -4 x-8 y & =-20 \\ 8 x+3 y & =1 \end{aligned}$

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Find the solution of the system of equations.\newline−4x−8yamp;=−208x+3yamp;=1 \begin{aligned} -4 x-8 y &amp; =-20 \\ 8 x+3 y &amp; =1 \end{aligned} −4x−8y8x+3y​amp;=−20amp;=1​

Find the solution of the system of equations. $\newline$ $\begin{aligned} -4 x-8 y & =-20 \\ 8 x+3 y & =1 \end{aligned}$