Q. Find the solution of the system of equations.4x−5y2x+15y=−11=47
Identify Equations: Identify the system of equations to solve.We have the following system of linear equations:4x−5y=−112x+15y=47We need to find the values of x and y that satisfy both equations simultaneously.
Prepare for Elimination: Multiply the second equation by 2 to prepare for elimination.Multiplying the second equation by 2 gives us:4x+30y=94This will allow us to eliminate x by subtracting this new equation from the first equation.
Eliminate x: Subtract the new second equation from the first equation to eliminate x.(4x−5y)−(4x+30y)=−11−94This simplifies to:−35y=−105
Solve for y: Solve for y.Divide both sides of the equation by −35 to find the value of y:y=−35−105y=3
Substitute and Solve for x: Substitute the value of y into one of the original equations to solve for x. Using the first equation 4x−5y=−11, we substitute y=3: 4x−5(3)=−114x−15=−11
Substitute and Solve for x: Substitute the value of y into one of the original equations to solve for x. Using the first equation 4x−5y=−11, we substitute y=3: 4x−5(3)=−114x−15=−11 Solve for x. Add 15 to both sides of the equation to isolate x: 4x=−11+15x0 Divide both sides by x1 to find the value of x: x3x4