Find the solution of the system of equations. {:[-4x+4y=-32],[9x+2y=-27]:} (◻,◻)

Question

Find the solution of the system of equations.  {:[-4x+4y=-32],[9x+2y=-27]:}  (◻,◻)

Bytelearn · Accepted Answer

Start by solving system: Let's start by solving the system of equations using the method of substitution or elimination. We will use the elimination method to solve this system of equations. First, we need to make the coefficients of one of the variables the same in both equations so we can eliminate that variable.Multiply second equation: To make the coefficients of y the same, we can multiply the second equation by 2. This will give us a new system of equations:  1st Equation: -4x + 4y = -32 2nd Equation (multiplied by 2): 18x + 4y = -54Subtract second equation: Now we can subtract the second equation from the first to eliminate y:  (-4x + 4y) - (18x + 4y) = -32 - (-54)  This simplifies to:  -4x + 4y - 18x - 4y = -32 + 54  The 4y terms cancel out, and we are left with:  -22x = 22Solve for x: We can now solve for x by dividing both sides of the equation by -22:  -22x / -22 = 22 / -22  x = -1Substitute back to find y: Now that we have the value of x, we can substitute it back into one of the original equations to find the value of y. We'll use the first equation:  -4(-1) + 4y = -32  4 + 4y = -32Isolate term with y: Next, we subtract 4 from both sides to isolate the term with y:  4y = -32 - 4  4y = -36Solve for y: Finally, we divide both sides by 4 to solve for y:  4y / 4 = -36 / 4  y = -9

Find the solution of the system of equations. $\newline$ $\begin{array}{r} -4 x+4 y=-32 \\ 9 x+2 y=-27 \end{array}$ $\newline$ $(\square, \square)$

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Find the solution of the system of equations.\newline−4x+4y=−329x+2y=−27 \begin{array}{r} -4 x+4 y=-32 \\ 9 x+2 y=-27 \end{array} −4x+4y=−329x+2y=−27​\newline(□,□) (\square, \square) (□,□)

Find the solution of the system of equations. $\newline$ $\begin{array}{r} -4 x+4 y=-32 \\ 9 x+2 y=-27 \end{array}$ $\newline$ $(\square, \square)$