Find the solution of the system of equations. {:[4x+2y=24],[8x-3y=-22]:}

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Find the solution of the system of equations.  {:[4x+2y=24],[8x-3y=-22]:}

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Write Equations: Write down the system of equations. We have the following system of equations: 4x + 2y = 24 8x - 3y = -22 We need to find the values of x and y that satisfy both equations simultaneously.Solve for y: Solve the first equation for y. We can express y in terms of x using the first equation: 4x + 2y = 24 2y = 24 - 4x y = (24 - 4x) / 2 y = 12 - 2x Now we have y expressed in terms of x.Substitute into Second Equation: Substitute the expression for y into the second equation. We will now substitute y = 12 - 2x into the second equation: 8x - 3(12 - 2x) = -22 This will allow us to solve for x.Simplify and Solve for x: Simplify and solve for x. 8x - 3(12 - 2x) = -22 8x - 36 + 6x = -22 Combine like terms: 14x - 36 = -22 Add 36 to both sides: 14x = 14 Divide by 14: x = 1 We have found the value of x.Substitute x into y Expression: Substitute x back into the expression for y. Now that we have x, we can find y by substituting x back into y = 12 - 2x: y = 12 - 2(1) y = 12 - 2 y = 10 We have found the value of y.

Find the solution of the system of equations. $\newline$ $\begin{array}{l} 4 x+2 y=24 \\ 8 x-3 y=-22 \end{array}$

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Find the solution of the system of equations.\newline4x+2y=248x−3y=−22 \begin{array}{l} 4 x+2 y=24 \\ 8 x-3 y=-22 \end{array} 4x+2y=248x−3y=−22​

Find the solution of the system of equations. $\newline$ $\begin{array}{l} 4 x+2 y=24 \\ 8 x-3 y=-22 \end{array}$