Find the solution of the system of equations. {:[3x+12 y=-33],[-5x+6y=3]:}

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Find the solution of the system of equations.  {:[3x+12 y=-33],[-5x+6y=3]:}

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Write Equations: Write down the system of equations to be solved. We have the following system of equations: 3x + 12y = -33 -5x + 6y = 3Multiply Second Equation: Multiply the second equation by 2 to make the coefficients of y the same. Multiplying the second equation by 2 gives us: -10x + 12y = 6 Now our system of equations is: 3x + 12y = -33 -10x + 12y = 6Eliminate y: Subtract the second equation from the first equation to eliminate y. (3x + 12y) - (-10x + 12y) = -33 - 6 This simplifies to: 3x + 12y + 10x - 12y = -33 - 6 Which further simplifies to: 13x = -39Solve for x: Solve for x. Divide both sides of the equation by 13 to isolate x: 13x / 13 = -39 / 13 x = -3Substitute and Solve for y: Substitute x = -3 into one of the original equations to solve for y. Using the first equation 3x + 12y = -33, substitute x with -3: 3(-3) + 12y = -33 -9 + 12y = -33Solve for y. Add 9 to both sides of the equation to isolate the term with y: -9 + 9 + 12y = -33 + 9 12y = -24 Divide both sides by 12 to solve for y: 12y / 12 = -24 / 12 y = -2

Find the solution of the system of equations. $\newline$ $\begin{aligned} 3 x+12 y & =-33 \\ -5 x+6 y & =3 \end{aligned}$

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Find the solution of the system of equations.\newline3x+12yamp;=−33−5x+6yamp;=3 \begin{aligned} 3 x+12 y &amp; =-33 \\ -5 x+6 y &amp; =3 \end{aligned} 3x+12y−5x+6y​amp;=−33amp;=3​

Find the solution of the system of equations. $\newline$ $\begin{aligned} 3 x+12 y & =-33 \\ -5 x+6 y & =3 \end{aligned}$