Find the solution of the system of equations. {:[-3x+12 y=-30],[-9x+6y=30]:}

Question

Find the solution of the system of equations.  {:[-3x+12 y=-30],[-9x+6y=30]:}

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Write Equations: Write down the system of equations to be solved. We have the following system of equations: -3x + 12y = -30 -9x + 6y = 30Eliminate Variable: Look for a way to eliminate one of the variables. We can multiply the first equation by 3 to make the coefficients of x in both equations the same (but opposite in sign), which will allow us to add the equations together to eliminate x. 3(-3x + 12y) = 3(-30) This gives us: -9x + 36y = -90Add Equations: Add the modified first equation to the second equation to eliminate x. (-9x + 36y) + (-9x + 6y) = -90 + 30 Combining like terms, we get: -18x + 42y = -60Correct Mistake: Realize there was a mistake in the previous step. The correct combination should be: (-9x + 36y) + (-9x + 6y) = -90 + 30 However, the coefficients of x are the same and not opposite in sign, so adding them will not eliminate x. We need to subtract the second equation from the modified first equation instead. (-9x + 36y) - (-9x + 6y) = -90 - 30

Find the solution of the system of equations. $\newline$ $\begin{aligned} -3 x+12 y & =-30 \\ -9 x+6 y & =30 \end{aligned}$

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Find the solution of the system of equations.\newline−3x+12yamp;=−30−9x+6yamp;=30 \begin{aligned} -3 x+12 y &amp; =-30 \\ -9 x+6 y &amp; =30 \end{aligned} −3x+12y−9x+6y​amp;=−30amp;=30​

Find the solution of the system of equations. $\newline$ $\begin{aligned} -3 x+12 y & =-30 \\ -9 x+6 y & =30 \end{aligned}$