Find the solution of the system of equations. {:[2x-3y=-1],[2x+y=19](_________,________)":}

Eliminate x: Subtract the second equation from the first to eliminate x. (2x - 3y) - (2x + y) = -1 - 19Simplify subtraction: Simplify the subtraction. -4y = -20Solve for y: Divide both sides by -4 to solve for y. y = -20 / -4Calculate y: Calculate the value of y. y = 5Solve for x: Substitute y = 5 into the second equation to solve for x. 2x + 5 = 19Substitute y into equation: Subtract 5 from both sides. 2x = 19 - 5Calculate 2x: Calculate the value of 2x. 2x = 14Solve for x: Divide both sides by 2 to solve for x. x = 14 / 2Calculate x: Calculate the value of x. x = 7

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Grade 8

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Q. Find the solution of the system of equations.

\newline

\begin{array}{c} 2 x-3 y=-1 \\ 2 x+y=19 \end{array}

\newline

(_________,________)

Eliminate x: Subtract the second equation from the first to eliminate x. $\newline$ $(2x - 3y) - (2x + y) = -1 - 19$
Simplify subtraction: Simplify the subtraction. $-4y = -20$
Solve for y: Divide both sides by $-4$ to solve for y. $\newline$ $y = \frac{-20}{-4}$
Calculate $y$ : Calculate the value of $y$ . $y = 5$
Solve for x: Substitute $y = 5$ into the second equation to solve for x. $2x + 5 = 19$
Substitute $y$ into equation: Subtract $5$ from both sides. $\newline$ $2x = 19 - 5$
Calculate $2x$ : Calculate the value of $2x$ . $2x = 14$
Solve for x: Divide both sides by $2$ to solve for x. $\newline$ $x = \frac{14}{2}$
Calculate $x$ : Calculate the value of $x$ . $x = 7$