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Find the solution of the system of equations.

{:[10 x-5y=-15],[5x-9y=12]:}

Find the solution of the system of equations.\newline10x5yamp;=155x9yamp;=12 \begin{aligned} 10 x-5 y & =-15 \\ 5 x-9 y & =12 \end{aligned}

Full solution

Q. Find the solution of the system of equations.\newline10x5y=155x9y=12 \begin{aligned} 10 x-5 y & =-15 \\ 5 x-9 y & =12 \end{aligned}
  1. Write Equations: Write down the system of equations.\newlineWe have the following system of equations:\newline10x5y=1510x - 5y = -15\newline5x9y=125x - 9y = 12\newlineWe need to find the values of xx and yy that satisfy both equations simultaneously.
  2. Multiply Second Equation: Multiply the second equation by 22 to make the coefficients of xx the same in both equations.\newlineMultiplying the second equation by 22 gives us:\newline2×(5x9y)=2×122 \times (5x - 9y) = 2 \times 12\newline10x18y=2410x - 18y = 24\newlineNow we have the new system of equations:\newline10x5y=1510x - 5y = -15\newline10x18y=2410x - 18y = 24
  3. Eliminate x: Subtract the first equation from the second equation to eliminate x.\newline(10x18y)(10x5y)=24(15)(10x - 18y) - (10x - 5y) = 24 - (-15)\newline10x18y10x+5y=24+1510x - 18y - 10x + 5y = 24 + 15\newline13y=39-13y = 39
  4. Solve for y: Solve for y.\newlineDivide both sides of the equation by 13-13 to find yy:\newliney=3913y = \frac{39}{-13}\newliney=3y = -3
  5. Substitute and Solve for xx: Substitute y=3y = -3 into one of the original equations to solve for xx.\newlineLet's use the first equation: 10x5y=1510x - 5y = -15\newline10x5(3)=1510x - 5(-3) = -15\newline10x+15=1510x + 15 = -15
  6. Substitute and Solve for xx: Substitute y=3y = -3 into one of the original equations to solve for xx. Let's use the first equation: 10x5y=1510x - 5y = -15 10x5(3)=1510x - 5(-3) = -15 10x+15=1510x + 15 = -15Solve for xx. Subtract 1515 from both sides of the equation: 10x=151510x = -15 - 15 10x=3010x = -30 Divide both sides by 1010: x=30/10x = -30 / 10 y=3y = -300