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Find the solution of the system of equations. 5x+10y=−55x+10y=-5 and −5x−y=32-5x-y=32

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Q. Find the solution of the system of equations. 5x+10y=−55x+10y=-5 and −5x−y=32-5x-y=32
  1. Eliminate xx: Add the two equations to eliminate xx.\newline5x+10y=−55x + 10y = -5\newline−5x−y=32-5x - y = 32\newline----------------\newline(5x−5x)+(10y−y)=−5+32(5x - 5x) + (10y - y) = -5 + 32\newline0x+9y=270x + 9y = 27
  2. Solve for y: Solve for y.\newline9y=279y = 27\newliney=279y = \frac{27}{9}\newliney=3y = 3
  3. Substitute to find xx: Substitute y=3y = 3 into the second equation to find xx.
    −5x−y=32-5x - y = 32
    −5x−3=32-5x - 3 = 32
    −5x=32+3-5x = 32 + 3
    −5x=35-5x = 35
    x=35−5x = \frac{35}{-5}
    x=−7x = -7

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