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Find the slope of the tangent line to k(x)=−1k(x) = -1 at x=11x = 11.\newlineWrite your answer as an integer or a fractions" target="_blank" class="backlink">fraction. Simplify any fractions.\newline____\newline

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Q. Find the slope of the tangent line to k(x)=−1k(x) = -1 at x=11x = 11.\newlineWrite your answer as an integer or a fraction. Simplify any fractions.\newline____\newline
  1. Identify Function and Point: Identify the function and the point of interest.\newlineFunction: k(x)=−1k(x) = -1, Point: x=11x = 11\newlineSince k(x)=−1k(x) = -1 is a constant function, its graph is a horizontal line.
  2. Determine Tangent Line Slope: Determine the slope of the tangent line.\newlineFor any constant function, the slope of the tangent line at any point is 00 because there is no change in the yy-values as xx changes.\newlineCalculation: Slope = 00

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