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Let’s check out your problem:
Find the quadratic polynomial that completes the factorization.
\newline
r
3
−
512
=
(
r
−
8
)
(
_
_
_
_
_
)
r^3 - 512 = (r - 8)(\_\_\_\_\_)
r
3
−
512
=
(
r
−
8
)
(
_____
)
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Math Problems
Precalculus
Factor sums and differences of cubes
Full solution
Q.
Find the quadratic polynomial that completes the factorization.
\newline
r
3
−
512
=
(
r
−
8
)
(
_
_
_
_
_
)
r^3 - 512 = (r - 8)(\_\_\_\_\_)
r
3
−
512
=
(
r
−
8
)
(
_____
)
Recognize as difference of cubes:
To factor
r
3
−
512
r^3 - 512
r
3
−
512
, recognize it as a difference of cubes:
r
3
−
8
3
r^3 - 8^3
r
3
−
8
3
.
Apply formula for factoring:
The formula for factoring a difference of cubes is
a
3
−
b
3
=
(
a
−
b
)
(
a
2
+
a
b
+
b
2
)
a^3 - b^3 = (a - b)(a^2 + ab + b^2)
a
3
−
b
3
=
(
a
−
b
)
(
a
2
+
ab
+
b
2
)
.
Factor using
a
a
a
and
b
b
b
:
Apply the formula with
a
=
r
a = r
a
=
r
and
b
=
8
b = 8
b
=
8
:
(
r
−
8
)
(
r
2
+
8
r
+
64
)
(r - 8)(r^2 + 8r + 64)
(
r
−
8
)
(
r
2
+
8
r
+
64
)
.
Check the multiplication:
Check the multiplication: r - \(8)(r^
2
2
2
+
8
8
8
r +
64
64
64
) = r^
3
3
3
+
8
8
8
r^
2
2
2
+
64
64
64
r -
8
8
8
r^
2
2
2
-
64
64
64
r -
512
512
512
\
Simplify the expression:
Simplify the expression:
r
3
+
8
r
2
+
64
r
−
8
r
2
−
64
r
−
512
=
r
3
−
512
r^3 + 8r^2 + 64r - 8r^2 - 64r - 512 = r^3 - 512
r
3
+
8
r
2
+
64
r
−
8
r
2
−
64
r
−
512
=
r
3
−
512
.
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\newline
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\newline
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(
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\newline
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24
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(
24
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Question
Is the function
q
(
x
)
=
x
6
−
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q(x) = x^6 - 9
q
(
x
)
=
x
6
−
9
even, odd, or neither?
\newline
Choices:
\newline
[[even][odd][neither]]
\text{[[even][odd][neither]]}
[[even][odd][neither]]
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Question
Find the product. Simplify your answer.
\newline
−
3
q
2
(
−
3
q
2
+
q
)
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−
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q
2
(
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3
q
2
+
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Question
Find the product. Simplify your answer.
\newline
(
r
+
3
)
(
4
r
+
2
)
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(
r
+
3
)
(
4
r
+
2
)
\newline
______
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Question
Find the roots of the factored polynomial.
\newline
(
x
+
7
)
(
x
+
4
)
(x + 7)(x + 4)
(
x
+
7
)
(
x
+
4
)
\newline
Write your answer as a list of values separated by commas.
\newline
x
=
x =
x
=
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Posted 9 months ago
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