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Let’s check out your problem:
Find the quadratic polynomial that completes the factorization.
\newline
w
3
+
125
=
(
w
+
5
)
(
_
_
_
_
_
)
w^3 + 125 = (w + 5)(\_\_\_\_\_)
w
3
+
125
=
(
w
+
5
)
(
_____
)
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Math Problems
Precalculus
Factor sums and differences of cubes
Full solution
Q.
Find the quadratic polynomial that completes the factorization.
\newline
w
3
+
125
=
(
w
+
5
)
(
_
_
_
_
_
)
w^3 + 125 = (w + 5)(\_\_\_\_\_)
w
3
+
125
=
(
w
+
5
)
(
_____
)
Factorize sum of cubes:
We know that
w
3
+
125
w^3 + 125
w
3
+
125
is a sum of cubes, which
factors
as
(
w
+
5
)
(
w
2
−
5
w
+
25
)
(w + 5)(w^2 - 5w + 25)
(
w
+
5
)
(
w
2
−
5
w
+
25
)
.
Expand factorized expression:
To check, we can expand
(
w
+
5
)
(
w
2
−
5
w
+
25
)
(w + 5)(w^2 - 5w + 25)
(
w
+
5
)
(
w
2
−
5
w
+
25
)
to see if it equals
w
3
+
125
w^3 + 125
w
3
+
125
.
(
w
+
5
)
(
w
2
−
5
w
+
25
)
=
w
3
−
5
w
2
+
25
w
+
5
w
2
−
25
w
+
125
(w + 5)(w^2 - 5w + 25) = w^3 - 5w^2 + 25w + 5w^2 - 25w + 125
(
w
+
5
)
(
w
2
−
5
w
+
25
)
=
w
3
−
5
w
2
+
25
w
+
5
w
2
−
25
w
+
125
.
Simplify the expression:
Simplify the expression:
w
3
−
5
w
2
+
25
w
+
5
w
2
−
25
w
+
125
=
w
3
+
125
w^3 - 5w^2 + 25w + 5w^2 - 25w + 125 = w^3 + 125
w
3
−
5
w
2
+
25
w
+
5
w
2
−
25
w
+
125
=
w
3
+
125
.
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\newline
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\newline
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\newline
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q
(
x
)
=
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−
9
even, odd, or neither?
\newline
Choices:
\newline
[[even][odd][neither]]
\text{[[even][odd][neither]]}
[[even][odd][neither]]
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\newline
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q
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\newline
(
r
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(
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r
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(
r
+
3
)
(
4
r
+
2
)
\newline
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Question
Find the roots of the factored polynomial.
\newline
(
x
+
7
)
(
x
+
4
)
(x + 7)(x + 4)
(
x
+
7
)
(
x
+
4
)
\newline
Write your answer as a list of values separated by commas.
\newline
x
=
x =
x
=
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