Find the product. Simplify your answer. (z - 4)(z + 4) ______

Identify Special Case: Identify the special case that applies to the given expression. The expression (z - 4)(z + 4) is in the form of (a - b)(a + b). Special case: (a - b)(a + b) = a^2 - b^2Identify Values: Identify the values of a and b. Compare (z - 4)(z + 4) with (a - b)(a + b). a = z b = 4Apply Formula: Apply the difference of squares formula to expand (z - 4)(z + 4). (a - b)(a + b) = a^2 - b^2 (z - 4)(z + 4) = z^2 - 4^2Simplify Expression: Simplify z^2 - 4^2. z^2 - 4^2 = z^2 - 16

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Find the product. Simplify your answer. $\newline$ $(z - 4)(z + 4)$

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Math Problems

Algebra 1

Multiply two binomials: special cases

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Q. Find the product. Simplify your answer.

\newline

(z - 4)(z + 4)

Identify Special Case: Identify the special case that applies to the given expression. $\newline$ The expression $(z - 4)(z + 4)$ is in the form of $(a - b)(a + b)$ . $\newline$ Special case: $(a - b)(a + b) = a^2 - b^2$
Identify Values: Identify the values of $a$ and $b$ . Compare $(z - 4)(z + 4)$ with $(a - b)(a + b)$ . $a = z$ $b = 4$
Apply Formula: Apply the difference of squares formula to expand $(z - 4)(z + 4)$ . $\newline$ $(a - b)(a + b) = a^2 - b^2$ $\newline$ $(z - 4)(z + 4) = z^2 - 4^2$
Simplify Expression: Simplify $z^2 - 4^2$ . $\newline$ $z^2 - 4^2 = z^2 - 16$