Find the product. Simplify your answer. (y + 3)(y - 4) ______

Apply Distributive Property: Apply the distributive property (also known as the FOIL method) to multiply the two binomials (y + 3) and (y - 4). (y + 3)(y - 4) = y(y - 4) + 3(y - 4)Multiply Binomials: Multiply y by each term in the binomial (y - 4). y(y - 4) = y*y - y*4 = y^2 - 4yCombine Terms: Multiply 3 by each term in the binomial (y - 4). 3(y - 4) = 3*y - 3*4 = 3y - 12Combine Like Terms: Combine the results from Step 2 and Step 3. (y + 3)(y - 4) = (y^2 - 4y) + (3y - 12) = y^2 - 4y + 3y - 12Combine like terms. y^2 - 4y + 3y - 12 = y^2 - (4y - 3y) - 12 = y^2 - 1y - 12

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Find the product. Simplify your answer. $\newline$ $(y + 3)(y - 4)$

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Math Problems

Algebra 1

Multiply two binomials

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Q. Find the product. Simplify your answer.

\newline

(y + 3)(y - 4)

Apply Distributive Property: Apply the distributive property (also known as the FOIL method) to multiply the two binomials $(y + 3)$ and $(y - 4)$ . $(y + 3)(y - 4) = y(y - 4) + 3(y - 4)$
Multiply Binomials: Multiply $y$ by each term in the binomial $(y - 4)$ . $y(y - 4) = y\times y - y\times 4$ $= y^2 - 4y$
Combine Terms: Multiply $3$ by each term in the binomial $(y - 4)$ . $\newline$ $3(y - 4) = 3\cdot y - 3\cdot 4$ $\newline$ $= 3y - 12$
Combine Like Terms: Combine the results from Step $2$ and Step $3$ . $\newline$ $(y + 3)(y - 4) = (y^2 - 4y) + (3y - 12)$ $\newline$ $= y^2 - 4y + 3y - 12$
Combine Like Terms: Combine the results from Step $2$ and Step $3$ . $\newline$ $(y + 3)(y - 4) = (y^2 - 4y) + (3y - 12)$ $\newline$ $= y^2 - 4y + 3y - 12$ Combine like terms. $\newline$ $y^2 - 4y + 3y - 12 = y^2 - (4y - 3y) - 12$ $\newline$ $= y^2 - 1y - 12$