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Let’s check out your problem:
Find the product. Simplify your answer.
\newline
(
w
+
1
)
(
2
w
−
4
)
(w + 1)(2w - 4)
(
w
+
1
)
(
2
w
−
4
)
View step-by-step help
Home
Math Problems
Algebra 1
Multiply two binomials
Full solution
Q.
Find the product. Simplify your answer.
\newline
(
w
+
1
)
(
2
w
−
4
)
(w + 1)(2w - 4)
(
w
+
1
)
(
2
w
−
4
)
Perform Multiplication:
Now, we will perform the multiplication for each term.
\newline
w
(
2
w
)
=
2
w
2
w(2w) = 2w^2
w
(
2
w
)
=
2
w
2
\newline
w
(
−
4
)
=
−
4
w
w(-4) = -4w
w
(
−
4
)
=
−
4
w
\newline
1
(
2
w
)
=
2
w
1(2w) = 2w
1
(
2
w
)
=
2
w
\newline
1
(
−
4
)
=
−
4
1(-4) = -4
1
(
−
4
)
=
−
4
Combine Like Terms:
Next, we will combine like terms.
2
w
2
+
(
−
4
w
)
+
2
w
+
(
−
4
)
=
2
w
2
−
4
w
+
2
w
−
4
2w^2 + (-4w) + 2w + (-4) = 2w^2 - 4w + 2w - 4
2
w
2
+
(
−
4
w
)
+
2
w
+
(
−
4
)
=
2
w
2
−
4
w
+
2
w
−
4
Simplify Expression:
Simplify the expression by combining the
w
w
w
terms.
2
w
2
−
4
w
+
2
w
−
4
=
2
w
2
−
2
w
−
4
2w^2 - 4w + 2w - 4 = 2w^2 - 2w - 4
2
w
2
−
4
w
+
2
w
−
4
=
2
w
2
−
2
w
−
4
Final Answer:
The expression is now fully simplified, and we have our final answer.
2
w
2
−
2
w
−
4
2w^2 - 2w - 4
2
w
2
−
2
w
−
4
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(
3
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)
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\newline
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\newline
(
24
t
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(
24
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Question
Is the function
q
(
x
)
=
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q
(
x
)
=
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6
−
9
even, odd, or neither?
\newline
Choices:
\newline
[[even][odd][neither]]
\text{[[even][odd][neither]]}
[[even][odd][neither]]
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Question
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\newline
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−
3
q
2
+
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)
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−
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q
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3
q
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+
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Find the product. Simplify your answer.
\newline
(
r
+
3
)
(
4
r
+
2
)
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(
r
+
3
)
(
4
r
+
2
)
\newline
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Question
Find the roots of the factored polynomial.
\newline
(
x
+
7
)
(
x
+
4
)
(x + 7)(x + 4)
(
x
+
7
)
(
x
+
4
)
\newline
Write your answer as a list of values separated by commas.
\newline
x
=
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=
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