Find the product. Simplify your answer. (t + 4)(2t - 1) ______

Apply Distributive Property: Apply the distributive property to multiply the two binomials. (t + 4)(2t - 1) = t(2t - 1) + 4(2t - 1)Multiply t by Binomial: Multiply t by each term in the binomial (2t - 1). t(2t - 1) = t(2t) - t(1) = 2t^2 - tMultiply 4 by Binomial: Multiply 4 by each term in the binomial (2t - 1). 4(2t - 1) = 4(2t) - 4(1) = 8t - 4Combine Results: Combine the results from Step 2 and Step 3. (2t^2 - t) + (8t - 4) = 2t^2 - t + 8t - 4Combine Like Terms: Combine like terms. 2t^2 - t + 8t - 4 = 2t^2 + (8t - t) - 4 = 2t^2 + 7t - 4

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Find the product. Simplify your answer. $\newline$ $(t + 4)(2t - 1)$

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Math Problems

Algebra 1

Multiply two binomials

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Q. Find the product. Simplify your answer.

\newline

(t + 4)(2t - 1)

Apply Distributive Property: Apply the distributive property to multiply the two binomials. $\newline$ $(t + 4)(2t - 1) = t(2t - 1) + 4(2t - 1)$
Multiply $t$ by Binomial: Multiply $t$ by each term in the binomial $(2t - 1)$ . $\newline$ $t(2t - 1) = t(2t) - t(1) = 2t^2 - t$
Multiply $4$ by Binomial: Multiply $4$ by each term in the binomial $(2t - 1)$ . $\newline$ $4(2t - 1) = 4(2t) - 4(1) = 8t - 4$
Combine Results: Combine the results from Step $2$ and Step $3$ . $\newline$ $(2t^2 - t) + (8t - 4) = 2t^2 - t + 8t - 4$
Combine Like Terms: Combine like terms. $2t^2 - t + 8t - 4 = 2t^2 + (8t - t) - 4 = 2t^2 + 7t - 4$