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Let’s check out your problem:
Find the product. Simplify your answer.
\newline
(
s
+
1
)
(
2
s
+
4
)
(s + 1)(2s + 4)
(
s
+
1
)
(
2
s
+
4
)
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Math Problems
Algebra 1
Multiply two binomials
Full solution
Q.
Find the product. Simplify your answer.
\newline
(
s
+
1
)
(
2
s
+
4
)
(s + 1)(2s + 4)
(
s
+
1
)
(
2
s
+
4
)
Distribute
s
s
s
to terms:
Now, we will distribute
s
s
s
to both terms in the first binomial.
s
(
2
s
+
4
)
=
s
(
2
s
)
+
s
(
4
)
=
2
s
2
+
4
s
s(2s + 4) = s(2s) + s(4) = 2s^2 + 4s
s
(
2
s
+
4
)
=
s
(
2
s
)
+
s
(
4
)
=
2
s
2
+
4
s
Distribute
1
1
1
to terms:
Next, we will distribute
1
1
1
to both terms in the second binomial.
\newline
1
(
2
s
+
4
)
=
1
(
2
s
)
+
1
(
4
)
=
2
s
+
4
1(2s + 4) = 1(2s) + 1(4) = 2s + 4
1
(
2
s
+
4
)
=
1
(
2
s
)
+
1
(
4
)
=
2
s
+
4
Combine like terms:
Now, we will combine like terms from the results of the previous two steps.
2
s
2
+
4
s
+
2
s
+
4
=
2
s
2
+
(
4
s
+
2
s
)
+
4
=
2
s
2
+
6
s
+
4
2s^2 + 4s + 2s + 4 = 2s^2 + (4s + 2s) + 4 = 2s^2 + 6s + 4
2
s
2
+
4
s
+
2
s
+
4
=
2
s
2
+
(
4
s
+
2
s
)
+
4
=
2
s
2
+
6
s
+
4
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(
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)
=
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−
9
even, odd, or neither?
\newline
Choices:
\newline
[[even][odd][neither]]
\text{[[even][odd][neither]]}
[[even][odd][neither]]
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\newline
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(
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)
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(
r
+
3
)
(
4
r
+
2
)
\newline
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Question
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\newline
(
x
+
7
)
(
x
+
4
)
(x + 7)(x + 4)
(
x
+
7
)
(
x
+
4
)
\newline
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\newline
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=
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