Find the product. Simplify your answer. (q - 3)(4q + 1) ______

Apply Distributive Property: Apply the distributive property to multiply the two binomials (q - 3) and (4q + 1). Distribute (4q + 1) with q and -3. (q - 3)(4q + 1) = q(4q + 1) - 3(4q + 1)Simplify q(4q + 1): Simplify q(4q + 1). Multiply q to 4q and 1. q(4q + 1) = q(4q) + q(1) = 4q^2 + qSimplify -3(4q + 1): Simplify -3(4q + 1). Multiply -3 to 4q and 1. -3(4q + 1) = -3(4q) - 3(1) = -12q - 3Combine Results: Combine the results from Step 2 and Step 3. 4q^2 + q - 12q - 3 Combine like terms. 4q^2 + q - 12q = 4q^2 - 11q So, the expression becomes 4q^2 - 11q - 3.

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Find the product. Simplify your answer. $\newline$ $(q - 3)(4q + 1)$

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Math Problems

Algebra 1

Multiply two binomials

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Q. Find the product. Simplify your answer.

\newline

(q - 3)(4q + 1)

Apply Distributive Property: Apply the distributive property to multiply the two binomials $(q - 3)$ and $(4q + 1)$ . $\newline$ Distribute $(4q + 1)$ with $q$ and $-3$ . $\newline$ $(q - 3)(4q + 1) = q(4q + 1) - 3(4q + 1)$
Simplify $q(4q + 1)$ : Simplify $q(4q + 1)$ . $\newline$ Multiply $q$ to $4q$ and $1$ . $\newline$ $q(4q + 1) = q(4q) + q(1) = 4q^2 + q$
Simplify $-3(4q + 1)$ : Simplify $-3(4q + 1)$ . $\newline$ Multiply $-3$ to $4q$ and $1$ . $\newline$ $-3(4q + 1) = -3(4q) - 3(1) = -12q - 3$
Combine Results: Combine the results from Step $2$ and Step $3$ . $\newline$ $4q^2 + q - 12q - 3$ $\newline$ Combine like terms. $\newline$ $4q^2 + q - 12q = 4q^2 - 11q$ $\newline$ So, the expression becomes $4q^2 - 11q - 3$ .