Find the product. Simplify your answer. (k + 1)(k - 1) ______

Identify special case: Identify the special case for the product (k + 1)(k - 1). This product is in the form of (a + b)(a - b), which is a difference of squares. Special case: (a + b)(a - b) = a^2 - b^2Identify values of a and b: Identify the values of a and b. Compare (k + 1)(k - 1) with (a + b)(a - b). a = k b = 1Apply difference of squares formula: Apply the difference of squares formula to expand (k + 1)(k - 1). (a + b)(a - b) = a^2 - b^2 (k + 1)(k - 1) = k^2 - 1^2Simplify expression: Simplify k^2 - 1^2. k^2 - 1^2 = k^2 - 1

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Find the product. Simplify your answer. $\newline$ $(k + 1)(k - 1)$

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Algebra 1

Multiply two binomials: special cases

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Q. Find the product. Simplify your answer.

\newline

(k + 1)(k - 1)

Identify special case: Identify the special case for the product $(k + 1)(k - 1)$ . This product is in the form of $(a + b)(a - b)$ , which is a difference of squares. Special case: $(a + b)(a - b) = a^2 - b^2$
Identify values of $a$ and $b$ : Identify the values of $a$ and $b$ . Compare $(k + 1)(k - 1)$ with $(a + b)(a - b)$ . $a = k$ $b = 1$
Apply difference of squares formula: Apply the difference of squares formula to expand $(k + 1)(k - 1)$ . $\newline$ $(a + b)(a - b) = a^2 - b^2$ $\newline$ $(k + 1)(k - 1) = k^2 - 1^2$
Simplify expression: Simplify $k^2 - 1^2$ . $\newline$ $k^2 - 1^2 = k^2 - 1$