Find the product. Simplify your answer. (j - 4)(3j - 3) ______

Apply Distributive Property: Apply the distributive property to multiply (j - 4) by each term in (3j - 3). (j - 4)(3j - 3) = j(3j - 3) - 4(3j - 3)Simplify j(3j - 3): Simplify j(3j - 3). j(3j - 3) = j(3j) - j(3) = 3j^2 - 3jSimplify -4(3j - 3): Simplify -4(3j - 3). -4(3j - 3) = -4(3j) + 4(3) = -12j + 12Combine Simplified Terms: Combine the simplified terms from the previous steps. (3j^2 - 3j) + (-12j + 12) = 3j^2 - 3j - 12j + 12Combine Like Terms: Combine like terms. 3j^2 - 3j - 12j + 12 = 3j^2 - 15j + 12

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Find the product. Simplify your answer. $\newline$ $(j - 4)(3j - 3)$

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Math Problems

Algebra 1

Multiply two binomials

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Q. Find the product. Simplify your answer.

\newline

(j - 4)(3j - 3)

Apply Distributive Property: Apply the distributive property to multiply $(j - 4)$ by each term in $(3j - 3)$ . $(j - 4)(3j - 3) = j(3j - 3) - 4(3j - 3)$
Simplify $j(3j - 3)$ : Simplify $j(3j - 3)$ . $j(3j - 3) = j(3j) - j(3) = 3j^2 - 3j$
Simplify $-4(3j - 3)$ : Simplify $-4(3j - 3)$ . $\newline$ $-4(3j - 3) = -4(3j) + 4(3) = -12j + 12$
Combine Simplified Terms: Combine the simplified terms from the previous steps. $\newline$ $(3j^2 - 3j) + (-12j + 12) = 3j^2 - 3j - 12j + 12$
Combine Like Terms: Combine like terms. $\newline$ $3j^2 - 3j - 12j + 12 = 3j^2 - 15j + 12$