Find the product. Simplify your answer. (b + 3)(b - 3) ______

Identify special case: Identify the special case for the product (b + 3)(b - 3). This product is in the form of (a + b)(a - b), which is a difference of squares. Special case: (a + b)(a - b) = a^2 - b^2Identify values of a and b: Identify the values of a and b. Compare (b + 3)(b - 3) with (a + b)(a - b). a = b b = 3Apply difference of squares formula: Apply the difference of squares formula to expand (b + 3)(b - 3). (a + b)(a - b) = a^2 - b^2 (b + 3)(b - 3) = b^2 - 3^2Simplify expression: Simplify b^2 - 3^2. b^2 - 3^2 = b^2 - 9

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Find the product. Simplify your answer. $\newline$ $(b + 3)(b - 3)$

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Algebra 1

Multiply two binomials: special cases

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Q. Find the product. Simplify your answer.

\newline

(b + 3)(b - 3)

Identify special case: Identify the special case for the product $(b + 3)(b - 3)$ . This product is in the form of $(a + b)(a - b)$ , which is a difference of squares. Special case: $(a + b)(a - b) = a^2 - b^2$
Identify values of $a$ and $b$ : Identify the values of $a$ and $b$ . Compare $(b + 3)(b - 3)$ with $(a + b)(a - b)$ . $a = b$ $b = 3$
Apply difference of squares formula: Apply the difference of squares formula to expand $(b + 3)(b - 3)$ . $\newline$ $(a + b)(a - b) = a^2 - b^2$ $\newline$ $(b + 3)(b - 3) = b^2 - 3^2$
Simplify expression: Simplify $b^2 - 3^2$ . $\newline$ $b^2 - 3^2 = b^2 - 9$