Find the product. Simplify your answer. (a + 4)(a - 4) ______

Identify special case: Identify the special case for the product (a + 4)(a - 4). This product is in the form of (a + b)(a - b), which is a difference of squares. Special case: (a + b)(a - b) = a^2 - b^2Apply difference of squares: Apply the difference of squares formula to the product (a + 4)(a - 4). Using the formula a^2 - b^2, we substitute a with a and b with 4. (a + 4)(a - 4) = a^2 - 4^2Calculate squares: Calculate the squares of a and 4. a^2 - 4^2 = a^2 - (4 * 4) = a^2 - 16Write final simplified form: Write the final simplified form of the product. The product (a + 4)(a - 4) simplifies to a^2 - 16.

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Find the product. Simplify your answer. $\newline$ $(a + 4)(a - 4)$

View step-by-step help

Home

Math Problems

Algebra 1

Multiply two binomials: special cases

Full solution

Q. Find the product. Simplify your answer.

\newline

(a + 4)(a - 4)

Identify special case: Identify the special case for the product $(a + 4)(a - 4)$ . This product is in the form of $(a + b)(a - b)$ , which is a difference of squares. Special case: $(a + b)(a - b) = a^2 - b^2$
Apply difference of squares: Apply the difference of squares formula to the product $(a + 4)(a - 4)$ . $\newline$ Using the formula $a^2 - b^2$ , we substitute $a$ with $a$ and $b$ with $4$ . $\newline$ $(a + 4)(a - 4) = a^2 - 4^2$
Calculate squares: Calculate the squares of $a$ and $4$ . $a^2 - 4^2 = a^2 - (4 \times 4) = a^2 - 16$
Write final simplified form: Write the final simplified form of the product. $\newline$ The product $(a + 4)(a - 4)$ simplifies to $a^2 - 16$ .