Find the product. Simplify your answer. (a + 4)(4a - 1) ______

Apply Distributive Property: Apply the distributive property to multiply the two binomials. (a + 4)(4a - 1) = a(4a - 1) + 4(4a - 1)Multiply 'a' Terms: Multiply 'a' by each term in the binomial (4a - 1). a(4a - 1) = a(4a) - a(1) = 4a^2 - aMultiply '4' Terms: Multiply '4' by each term in the binomial (4a - 1). 4(4a - 1) = 4(4a) - 4(1) = 16a - 4Combine Results: Combine the results from Step 2 and Step 3. (4a^2 - a) + (16a - 4) = 4a^2 - a + 16a - 4Combine Like Terms: Combine like terms. 4a^2 - a + 16a - 4 = 4a^2 + (16a - a) - 4 = 4a^2 + 15a - 4

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Find the product. Simplify your answer. $\newline$ $(a + 4)(4a - 1)$

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Math Problems

Algebra 1

Multiply two binomials

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Q. Find the product. Simplify your answer.

\newline

(a + 4)(4a - 1)

Apply Distributive Property: Apply the distributive property to multiply the two binomials. $\newline$ $(a + 4)(4a - 1) = a(4a - 1) + 4(4a - 1)$
Multiply 'a' Terms: Multiply $a$ by each term in the binomial $(4a - 1)$ . $a(4a - 1) = a(4a) - a(1)$ $= 4a^2 - a$
Multiply ' $4$ ' Terms: Multiply $4$ by each term in the binomial $(4a - 1)$ . $4(4a - 1) = 4(4a) - 4(1)$ $= 16a - 4$
Combine Results: Combine the results from Step $2$ and Step $3$ . $\newline$ $(4a^2 - a) + (16a - 4)$ $\newline$ $= 4a^2 - a + 16a - 4$
Combine Like Terms: Combine like terms. $\newline$ $4a^2 - a + 16a - 4$ $\newline$ = $4a^2 + (16a - a) - 4$ $\newline$ = $4a^2 + 15a - 4$