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Find the product. Simplify your answer.\newline6(2j2+3j)-6(2j^2 + 3j)

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Q. Find the product. Simplify your answer.\newline6(2j2+3j)-6(2j^2 + 3j)
  1. Identify and Distribute: Identify the expression and use the distributive property.\newlineDistribute 6-6 to 2j22j^2 and 3j3j.\newline6(2j2+3j)=6(2j2)6(3j)-6(2j^2 + 3j) = -6(2j^2) - 6(3j)
  2. Simplify 2j22j^2: Simplify 6(2j2)-6(2j^2). Multiply 6-6 and 2j22j^2. 6(2j2)=12j2-6(2j^2) = -12j^2
  3. Simplify 3j3j: Simplify 6(3j)-6(3j).\newlineMultiply 6-6 and 3j3j.\newline6(3j)=18j-6(3j) = -18j
  4. Combine Results: Combine the results from Step 22 and Step 33.\newlineWe found:\newline6(2j2)=12j2-6(2j^2) = -12j^2\newline6(3j)=18j-6(3j) = -18j\newlineThe simplified form of 6(2j2+3j)-6(2j^2 + 3j) is 12j218j-12j^2 - 18j.

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