Find the product. Simplify your answer. (4y + 4)(4y - 4) ______

Identify Form of Expression: Identify the form of the expression. The expression (4y + 4)(4y - 4) is in the form of (a + b)(a - b), which is a difference of squares. Special case: (a + b)(a - b) = a^2 - b^2Identify Values of a and b: Identify the values of a and b. Compare (4y + 4)(4y - 4) with (a + b)(a - b). a = 4y b = 4Apply Difference of Squares Formula: Apply the difference of squares formula. Using the values of a and b, we apply the formula (a + b)(a - b) = a^2 - b^2. (4y + 4)(4y - 4) = (4y)^2 - (4)^2Simplify the Expression: Simplify the expression. (4y)^2 - (4)^2 = (4y * 4y) - (4 * 4) = 16y^2 - 16

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Find the product. Simplify your answer. $\newline$ $(4y + 4)(4y - 4)$

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Algebra 1

Multiply two binomials: special cases

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Q. Find the product. Simplify your answer.

\newline

(4y + 4)(4y - 4)

Identify Form of Expression: Identify the form of the expression. $\newline$ The expression $(4y + 4)(4y - 4)$ is in the form of $(a + b)(a - b)$ , which is a difference of squares. $\newline$ Special case: $(a + b)(a - b) = a^2 - b^2$
Identify Values of $a$ and $b$ : Identify the values of $a$ and $b$ . Compare $(4y + 4)(4y - 4)$ with $(a + b)(a - b)$ . $a = 4y$ $b = 4$
Apply Difference of Squares Formula: Apply the difference of squares formula. $\newline$ Using the values of $a$ and $b$ , we apply the formula $(a + b)(a - b) = a^2 - b^2$ . $\newline$ $(4y + 4)(4y - 4) = (4y)^2 - (4)^2$
Simplify the Expression: Simplify the expression. $\newline$ $(4y)^2 - (4)^2$ $\newline$ = $(4y \times 4y) - (4 \times 4)$ $\newline$ = $16y^2 - 16$