Find the product. Simplify your answer. (4y+1)(y-1)

Distribute terms: Distribute each term in (4y+1) to each term in (y-1). (4y+1)(y-1) = 4y(y) + 4y(-1) + 1(y) + 1(-1)Perform multiplication: Perform the multiplication for each term. 4y(y) = 4y^2, 4y(-1) = -4y, 1(y) = y, 1(-1) = -1 Combine all terms: 4y^2 - 4y + y - 1Combine terms: Simplify by combining like terms. 4y^2 - 4y + y - 1 = 4y^2 - 3y - 1

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Find the product. Simplify your answer.

(4y+1)(y-1)

Find the product. Simplify your answer. $\newline$ $(4 y+1)(y-1)$

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Q. Find the product. Simplify your answer.

\newline

(4 y+1)(y-1)

Distribute terms: Distribute each term in $(4y+1)$ to each term in $(y-1)$ . $(4y+1)(y-1) = 4y(y) + 4y(-1) + 1(y) + 1(-1)$
Perform multiplication: Perform the multiplication for each term. $\newline$ $4y(y) = 4y^2$ , $4y(-1) = -4y$ , $1(y) = y$ , $1(-1) = -1$ $\newline$ Combine all terms: $4y^2 - 4y + y - 1$
Combine terms: Simplify by combining like terms. $\newline$ $4y^2 - 4y + y - 1 = 4y^2 - 3y - 1$