Find the product. Simplify your answer. (4w + 2)(4w - 2) ______

Identify special case: Identify the special case for the product (4w + 2)(4w - 2). This product is in the form of (a + b)(a - b), which is a difference of squares. Special case: (a + b)(a - b) = a^2 - b^2Identify values of a and b: Identify the values of a and b. Compare (4w + 2)(4w - 2) with (a + b)(a - b). a = 4w b = 2Apply difference of squares formula: Apply the difference of squares formula to expand (4w + 2)(4w - 2). (a + b)(a - b) = a^2 - b^2 (4w + 2)(4w - 2) = (4w)^2 - (2)^2Simplify expression: Simplify (4w)^2 - (2)^2. (4w)^2 - (2)^2 = (4w * 4w) - (2 * 2) = 16w^2 - 4

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Find the product. Simplify your answer. $\newline$ $(4w + 2)(4w - 2)$

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Algebra 1

Multiply two binomials: special cases

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Q. Find the product. Simplify your answer.

\newline

(4w + 2)(4w - 2)

Identify special case: Identify the special case for the product $(4w + 2)(4w - 2)$ . This product is in the form of $(a + b)(a - b)$ , which is a difference of squares. Special case: $(a + b)(a - b) = a^2 - b^2$
Identify values of $a$ and $b$ : Identify the values of $a$ and $b$ . Compare $(4w + 2)(4w - 2)$ with $(a + b)(a - b)$ . $a = 4w$ $b = 2$
Apply difference of squares formula: Apply the difference of squares formula to expand $(4w + 2)(4w - 2)$ . $\newline$ $(a + b)(a - b) = a^2 - b^2$ $\newline$ $(4w + 2)(4w - 2) = (4w)^2 - (2)^2$
Simplify expression: Simplify $(4w)^2 - (2)^2.$ $(4w)^2 - (2)^2 = (4w \times 4w) - (2 \times 2)$ $= 16w^2 - 4$