Find the product. Simplify your answer. (4s - 2)(4s + 2) ______

Identify special case: Identify the special case for the product (4s - 2)(4s + 2). This product is in the form of (a - b)(a + b), which is a difference of squares. Special case: (a - b)(a + b) = a^2 - b^2Identify values of a and b: Identify the values of a and b. Compare (4s - 2)(4s + 2) with (a - b)(a + b). a = 4s b = 2Apply difference of squares formula: Apply the difference of squares formula to expand (4s - 2)(4s + 2). (a - b)(a + b) = a^2 - b^2 (4s - 2)(4s + 2) = (4s)^2 - (2)^2Simplify expression: Simplify (4s)^2 - (2)^2. (4s)^2 - (2)^2 = (4s * 4s) - (2 * 2) = 16s^2 - 4

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Find the product. Simplify your answer. $\newline$ $(4s - 2)(4s + 2)$

View step-by-step help

Home

Math Problems

Algebra 1

Multiply two binomials: special cases

Full solution

Q. Find the product. Simplify your answer.

\newline

(4s - 2)(4s + 2)

Identify special case: Identify the special case for the product $(4s - 2)(4s + 2)$ . This product is in the form of $(a - b)(a + b)$ , which is a difference of squares. Special case: $(a - b)(a + b) = a^2 - b^2$
Identify values of $a$ and $b$ : Identify the values of $a$ and $b$ . Compare $(4s - 2)(4s + 2)$ with $(a - b)(a + b)$ . $a = 4s$ $b = 2$
Apply difference of squares formula: Apply the difference of squares formula to expand $(4s - 2)(4s + 2)$ . $\newline$ $(a - b)(a + b) = a^2 - b^2$ $\newline$ $(4s - 2)(4s + 2) = (4s)^2 - (2)^2$
Simplify expression: Simplify $(4s)^2 - (2)^2.$ $(4s)^2 - (2)^2 = (4s \times 4s) - (2 \times 2)$ $= 16s^2 - 4$