Find the product. Simplify your answer. (4s - 2)(3s - 3) ______

Apply Distributive Property: We need to apply the distributive property to multiply the two binomials (4s - 2) and (3s - 3). First, distribute each term of the first binomial across the second binomial. (4s - 2)(3s - 3) = 4s(3s) + 4s(-3) - 2(3s) - 2(-3)Simplify Multiplications: Now, we will simplify each multiplication. 4s(3s) = 12s^2 (Multiplying the coefficients and adding the exponents for s) 4s(-3) = -12s (Multiplying the coefficient of s by -3) -2(3s) = -6s (Multiplying -2 by the coefficient of s) -2(-3) = 6 (Multiplying -2 by -3)Combine Results: Combine the results of the multiplications to get the expanded form. (4s - 2)(3s - 3) = 12s^2 - 12s - 6s + 6Combine Like Terms: Combine like terms to simplify the expression further. 12s^2 - 12s - 6s + 6 = 12s^2 - 18s + 6

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Math Problems

Algebra 1

Multiply two binomials

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Q. Find the product. Simplify your answer.

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(4s - 2)(3s - 3)

Apply Distributive Property: We need to apply the distributive property to multiply the two binomials $(4s - 2)$ and $(3s - 3)$ . First, distribute each term of the first binomial across the second binomial. $(4s - 2)(3s - 3) = 4s(3s) + 4s(-3) - 2(3s) - 2(-3)$
Simplify Multiplications: Now, we will simplify each multiplication. $\newline$ $4s(3s) = 12s^2$ (Multiplying the coefficients and adding the exponents for $s$ ) $\newline$ $4s(-3) = -12s$ (Multiplying the coefficient of $s$ by $-3$ ) $\newline$ $-2(3s) = -6s$ (Multiplying $-2$ by the coefficient of $s$ ) $\newline$ $-2(-3) = 6$ (Multiplying $-2$ by $-3$ )
Combine Results: Combine the results of the multiplications to get the expanded form. $\newline$ $(4s - 2)(3s - 3) = 12s^2 - 12s - 6s + 6$
Combine Like Terms: Combine like terms to simplify the expression further. $12s^2 - 12s - 6s + 6 = 12s^2 - 18s + 6$