Find the product. Simplify your answer. (4q + 4)(4q - 4) ______

Identify special case: Identify the special case for the product (4q + 4)(4q - 4). This product is in the form of (a + b)(a - b), which is a difference of squares. Special case: (a + b)(a - b) = a^2 - b^2Identify values of a and b: Identify the values of a and b. Compare (4q + 4)(4q - 4) with (a + b)(a - b). a = 4q b = 4Apply difference of squares formula: Apply the difference of squares formula to expand (4q + 4)(4q - 4). (a + b)(a - b) = a^2 - b^2 (4q + 4)(4q - 4) = (4q)^2 - (4)^2Simplify expression: Simplify (4q)^2 - (4)^2. (4q)^2 - (4)^2 = (4q * 4q) - (4 * 4) = 16q^2 - 16

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Find the product. Simplify your answer. $\newline$ $(4q + 4)(4q - 4)$

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Algebra 1

Multiply two binomials: special cases

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Q. Find the product. Simplify your answer.

\newline

(4q + 4)(4q - 4)

Identify special case: Identify the special case for the product $(4q + 4)(4q - 4)$ . This product is in the form of $(a + b)(a - b)$ , which is a difference of squares. Special case: $(a + b)(a - b) = a^2 - b^2$
Identify values of $a$ and $b$ : Identify the values of $a$ and $b$ . Compare $(4q + 4)(4q - 4)$ with $(a + b)(a - b)$ . $a = 4q$ $b = 4$
Apply difference of squares formula: Apply the difference of squares formula to expand $(4q + 4)(4q - 4)$ . $\newline$ $(a + b)(a - b) = a^2 - b^2$ $\newline$ $(4q + 4)(4q - 4) = (4q)^2 - (4)^2$
Simplify expression: Simplify ($4q)^ $2$ - ( $4$ )^ $2$ .(\newline$($4q)^ $2$ - ( $4$ )^ $2$ (\newline$= ( $4$ q \times $4$ q) - ( $4$ \times $4$ )(\newline\)= $16$ q^ $2$ - $16$