Find the product. Simplify your answer. (4q + 3)(4q - 3) ______

Identify Special Case: Identify the special case that applies to the given expression. The expression (4q + 3)(4q - 3) is in the form of (a + b)(a - b). Special case: (a + b)(a - b) = a^2 - b^2Identify Values of a and b: Identify the values of a and b. Compare (4q + 3)(4q - 3) with (a + b)(a - b). a = 4q b = 3Apply Difference of Squares Formula: Apply the difference of squares formula to expand (4q + 3)(4q - 3). (a + b)(a - b) = a^2 - b^2 (4q + 3)(4q - 3) = (4q)^2 - (3)^2Simplify Expression: Simplify (4q)^2 - (3)^2. (4q)^2 - (3)^2 = (4q * 4q) - (3 * 3) = 16q^2 - 9

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Find the product. Simplify your answer. $\newline$ $(4q + 3)(4q - 3)$

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Math Problems

Algebra 1

Multiply two binomials: special cases

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Q. Find the product. Simplify your answer.

\newline

(4q + 3)(4q - 3)

Identify Special Case: Identify the special case that applies to the given expression. $\newline$ The expression $(4q + 3)(4q - 3)$ is in the form of $(a + b)(a - b)$ . $\newline$ Special case: $(a + b)(a - b) = a^2 - b^2$
Identify Values of $a$ and $b$ : Identify the values of $a$ and $b$ . Compare $(4q + 3)(4q - 3)$ with $(a + b)(a - b)$ . $a = 4q$ $b = 3$
Apply Difference of Squares Formula: Apply the difference of squares formula to expand $(4q + 3)(4q - 3)$ . $\newline$ $(a + b)(a - b) = a^2 - b^2$ $\newline$ $(4q + 3)(4q - 3) = (4q)^2 - (3)^2$
Simplify Expression: Simplify $(4q)^2 - (3)^2.$ $(4q)^2 - (3)^2 = (4q \times 4q) - (3 \times 3)$ $= 16q^2 - 9$