Find the product. Simplify your answer. (4m - 1)(4m + 1) ______

Identify Special Case: Identify the special case that applies to the given expression. The expression (4m - 1)(4m + 1) is in the form of (a - b)(a + b). Special case: (a - b)(a + b) = a^2 - b^2Identify Values of a and b: Identify the values of a and b. Compare (4m - 1)(4m + 1) with (a - b)(a + b). a = 4m b = 1Apply Difference of Squares Formula: Apply the difference of squares formula to expand (4m - 1)(4m + 1). (a - b)(a + b) = a^2 - b^2 (4m - 1)(4m + 1) = (4m)^2 - (1)^2Simplify Expression: Simplify (4m)^2 - (1)^2. (4m)^2 - (1)^2 = (4m * 4m) - (1 * 1) = 16m^2 - 1

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Find the product. Simplify your answer. $\newline$ $(4m - 1)(4m + 1)$

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Math Problems

Algebra 1

Multiply two binomials: special cases

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Q. Find the product. Simplify your answer.

\newline

(4m - 1)(4m + 1)

Identify Special Case: Identify the special case that applies to the given expression. $\newline$ The expression $(4m - 1)(4m + 1)$ is in the form of $(a - b)(a + b)$ . $\newline$ Special case: $(a - b)(a + b) = a^2 - b^2$
Identify Values of $a$ and $b$ : Identify the values of $a$ and $b$ . Compare $(4m - 1)(4m + 1)$ with $(a - b)(a + b)$ . $a = 4m$ $b = 1$
Apply Difference of Squares Formula: Apply the difference of squares formula to expand $(4m - 1)(4m + 1)$ . $\newline$ $(a - b)(a + b) = a^2 - b^2$ $\newline$ $(4m - 1)(4m + 1) = (4m)^2 - (1)^2$
Simplify Expression: Simplify $(4m)^2 - (1)^2.$ $(4m)^2 - (1)^2 = (4m \times 4m) - (1 \times 1)$ $= 16m^2 - 1$