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Let’s check out your problem:
Find the product. Simplify your answer.
\newline
(
4
j
+
2
)
(
j
+
4
)
(4j + 2)(j + 4)
(
4
j
+
2
)
(
j
+
4
)
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Math Problems
Algebra 1
Multiply two binomials
Full solution
Q.
Find the product. Simplify your answer.
\newline
(
4
j
+
2
)
(
j
+
4
)
(4j + 2)(j + 4)
(
4
j
+
2
)
(
j
+
4
)
Distribute
4
j
4j
4
j
:
Now, we will distribute
4
j
4j
4
j
across the terms inside the parentheses.
4
j
(
j
+
4
)
=
4
j
×
j
+
4
j
×
4
4j(j + 4) = 4j \times j + 4j \times 4
4
j
(
j
+
4
)
=
4
j
×
j
+
4
j
×
4
=
4
j
2
+
16
j
= 4j^2 + 16j
=
4
j
2
+
16
j
Distribute
2
2
2
:
Next, we will distribute
2
2
2
across the terms inside the parentheses.
\newline
2(j + 4) = 2 \times j + 2 \times 4\(\newline= 2j + 8\)
Combine terms:
Now, we will combine the results from the previous steps.
\newline
(
4
j
+
2
)
(
j
+
4
)
=
4
j
2
+
16
j
+
2
j
+
8
(4j + 2)(j + 4) = 4j^2 + 16j + 2j + 8
(
4
j
+
2
)
(
j
+
4
)
=
4
j
2
+
16
j
+
2
j
+
8
Simplify expression:
Finally, we will combine like terms to simplify the expression.
\newline
4
j
2
+
16
j
+
2
j
+
8
=
4
j
2
+
(
16
j
+
2
j
)
+
8
4j^2 + 16j + 2j + 8 = 4j^2 + (16j + 2j) + 8
4
j
2
+
16
j
+
2
j
+
8
=
4
j
2
+
(
16
j
+
2
j
)
+
8
\newline
=
4
j
2
+
18
j
+
8
= 4j^2 + 18j + 8
=
4
j
2
+
18
j
+
8
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=
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−
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\newline
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\text{[[even][odd][neither]]}
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Find the product. Simplify your answer.
\newline
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)
(
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+
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)
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(
r
+
3
)
(
4
r
+
2
)
\newline
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\newline
(
x
+
7
)
(
x
+
4
)
(x + 7)(x + 4)
(
x
+
7
)
(
x
+
4
)
\newline
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\newline
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