Find the product. Simplify your answer. (4b - 1)(4b + 1) ______

Identify special case: Identify the special case for the product (4b - 1)(4b + 1). This product is in the form of (a - b)(a + b), which is a difference of squares. Special case: (a - b)(a + b) = a^2 - b^2Identify values of a and b: Identify the values of a and b. Compare (4b - 1)(4b + 1) with (a - b)(a + b). a = 4b b = 1Apply difference of squares formula: Apply the difference of squares formula to expand (4b - 1)(4b + 1). (a - b)(a + b) = a^2 - b^2 (4b - 1)(4b + 1) = (4b)^2 - 1^2Simplify expression: Simplify (4b)^2 - 1^2. (4b)^2 - 1^2 = (4b * 4b) - (1 * 1) = 16b^2 - 1

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Find the product. Simplify your answer. $\newline$ $(4b - 1)(4b + 1)$

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Algebra 1

Multiply two binomials: special cases

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Q. Find the product. Simplify your answer.

\newline

(4b - 1)(4b + 1)

Identify special case: Identify the special case for the product $(4b - 1)(4b + 1)$ . This product is in the form of $(a - b)(a + b)$ , which is a difference of squares. Special case: $(a - b)(a + b) = a^2 - b^2$
Identify values of $a$ and $b$ : Identify the values of $a$ and $b$ . Compare $(4b - 1)(4b + 1)$ with $(a - b)(a + b)$ . $a = 4b$ $b = 1$
Apply difference of squares formula: Apply the difference of squares formula to expand $(4b - 1)(4b + 1)$ . $\newline$ $(a - b)(a + b) = a^2 - b^2$ $\newline$ $(4b - 1)(4b + 1) = (4b)^2 - 1^2$
Simplify expression: Simplify $(4b)^2 - 1^2.$ $(4b)^2 - 1^2 = (4b \times 4b) - (1 \times 1) = 16b^2 - 1$