Find the product. Simplify your answer. (4a - 3)(4a + 3) ______

Identify Special Case: Identify the special case that applies to this problem. The expression (4a - 3)(4a + 3) is in the form of (a - b)(a + b). Special case: (a - b)(a + b) = a^2 - b^2Identify Values: Identify the values of a and b. Compare (4a - 3)(4a + 3) with (a - b)(a + b). a = 4a b = 3Apply Difference of Squares: Apply the difference of squares to expand (4a - 3)(4a + 3). (a - b)(a + b) = a^2 - b^2 (4a - 3)(4a + 3) = (4a)^2 - (3)^2Simplify Expression: Simplify (4a)^2 - (3)^2. (4a)^2 - (3)^2 = (4a * 4a) - (3 * 3) = 16a^2 - 9

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Find the product. Simplify your answer. $\newline$ $(4a - 3)(4a + 3)$

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Math Problems

Algebra 1

Multiply two binomials: special cases

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Q. Find the product. Simplify your answer.

\newline

(4a - 3)(4a + 3)

Identify Special Case: Identify the special case that applies to this problem. $\newline$ The expression $(4a - 3)(4a + 3)$ is in the form of $(a - b)(a + b)$ . $\newline$ Special case: $(a - b)(a + b) = a^2 - b^2$
Identify Values: Identify the values of $a$ and $b$ . Compare $(4a - 3)(4a + 3)$ with $(a - b)(a + b)$ . $a = 4a$ $b = 3$
Apply Difference of Squares: Apply the difference of squares to expand $(4a - 3)(4a + 3)$ . $(a - b)(a + b) = a^2 - b^2$ $(4a - 3)(4a + 3) = (4a)^2 - (3)^2$
Simplify Expression: Simplify $(4a)^2 - (3)^2.$ $(4a)^2 - (3)^2 = (4a \times 4a) - (3 \times 3)$ $= 16a^2 - 9$