Find the product. Simplify your answer. (3w - 4)(3w + 4) ______

Identify Special Case: Identify the special case for the product (3w - 4)(3w + 4). This product is in the form of (a - b)(a + b), which is a difference of squares. Special case: (a - b)(a + b) = a^2 - b^2Identify Values of a and b: Identify the values of a and b. Compare (3w - 4)(3w + 4) with (a - b)(a + b). a = 3w b = 4Apply Difference of Squares Formula: Apply the difference of squares formula to expand (3w - 4)(3w + 4). (a - b)(a + b) = a^2 - b^2 (3w - 4)(3w + 4) = (3w)^2 - (4)^2Simplify Expression: Simplify (3w)^2 - (4)^2. (3w)^2 - (4)^2 = (3w * 3w) - (4 * 4) = 9w^2 - 16

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Find the product. Simplify your answer. $\newline$ $(3w - 4)(3w + 4)$

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Algebra 1

Multiply two binomials: special cases

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Q. Find the product. Simplify your answer.

\newline

(3w - 4)(3w + 4)

Identify Special Case: Identify the special case for the product $(3w - 4)(3w + 4)$ . This product is in the form of $(a - b)(a + b)$ , which is a difference of squares. Special case: $(a - b)(a + b) = a^2 - b^2$
Identify Values of $a$ and $b$ : Identify the values of $a$ and $b$ . Compare $(3w - 4)(3w + 4)$ with $(a - b)(a + b)$ . $a = 3w$ $b = 4$
Apply Difference of Squares Formula: Apply the difference of squares formula to expand $(3w - 4)(3w + 4)$ . $\newline$ $(a - b)(a + b) = a^2 - b^2$ $\newline$ $(3w - 4)(3w + 4) = (3w)^2 - (4)^2$
Simplify Expression: Simplify $(3w)^2 - (4)^2.$ $(3w)^2 - (4)^2$ $= (3w \times 3w) - (4 \times 4)$ $= 9w^2 - 16$