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Find the product. Simplify your answer.\newline(3u+3)(3u3)(3u + 3)(3u - 3)

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Q. Find the product. Simplify your answer.\newline(3u+3)(3u3)(3u + 3)(3u - 3)
  1. Identify Problem Structure: Identify the structure of the problem.\newlineWe are asked to find the product of two binomials: (3u+3)(3u3)(3u + 3)(3u - 3).\newlineThis is in the form of (a+b)(ab)(a + b)(a - b), which is a difference of squares.
  2. Apply Difference of Squares: Apply the difference of squares formula. The difference of squares formula is (a+b)(ab)=a2b2(a + b)(a - b) = a^2 - b^2. Here, a=3ua = 3u and b=3b = 3.
  3. Calculate Squares of a and b: Calculate the squares of aa and bb.\newlineSquare aa: (3u)2=9u2(3u)^2 = 9u^2.\newlineSquare bb: 32=93^2 = 9.
  4. Subtract Squares: Subtract the square of bb from the square of aa. Using the difference of squares formula: 9u299u^2 - 9.
  5. Simplify Expression: Simplify the expression.\newlineThe simplified form of the product is 9u299u^2 - 9.

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