Find the product. Simplify your answer. (3r + 3)(3r - 3) ______

Identify Form: Identify the form of the expression. The expression (3r + 3)(3r - 3) is in the form of (a + b)(a - b), which is a difference of squares. Special case: (a + b)(a - b) = a^2 - b^2Identify Values: Identify the values of a and b. Compare (3r + 3)(3r - 3) with (a + b)(a - b). a = 3r b = 3Apply Formula: Apply the difference of squares formula to expand (3r + 3)(3r - 3). (a + b)(a - b) = a^2 - b^2 (3r + 3)(3r - 3) = (3r)^2 - (3)^2Simplify: Simplify (3r)^2 - (3)^2. (3r)^2 - (3)^2 = (3r * 3r) - (3 * 3) = 9r^2 - 9

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Find the product. Simplify your answer. $\newline$ $(3r + 3)(3r - 3)$

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Math Problems

Algebra 1

Multiply two binomials: special cases

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Q. Find the product. Simplify your answer.

\newline

(3r + 3)(3r - 3)

Identify Form: Identify the form of the expression. $\newline$ The expression $(3r + 3)(3r - 3)$ is in the form of $(a + b)(a - b)$ , which is a difference of squares. $\newline$ Special case: $(a + b)(a - b) = a^2 - b^2$
Identify Values: Identify the values of $a$ and $b$ . Compare $(3r + 3)(3r - 3)$ with $(a + b)(a - b)$ . $a = 3r$ $b = 3$
Apply Formula: Apply the difference of squares formula to expand $(3r + 3)(3r - 3)$ . $\newline$ $(a + b)(a - b) = a^2 - b^2$ $\newline$ $(3r + 3)(3r - 3) = (3r)^2 - (3)^2$
Simplify: Simplify $(3r)^2 - (3)^2.$ $(3r)^2 - (3)^2 = (3r \times 3r) - (3 \times 3)$ $= 9r^2 - 9$