Find the product. Simplify your answer. (3r - 1)(r + 2) ______

Apply Distributive Property: Apply the distributive property to multiply the two binomials. (3r - 1)(r + 2) = 3r(r + 2) - 1(r + 2)Distribute 3r: Distribute 3r to both terms in the second binomial. 3r(r + 2) = 3r * r + 3r * 2 = 3r^2 + 6rDistribute -1: Distribute -1 to both terms in the second binomial. -1(r + 2) = -1 * r - 1 * 2 = -r - 2Combine Results: Combine the results from Step 2 and Step 3. (3r - 1)(r + 2) = 3r^2 + 6r - r - 2Combine Like Terms: Combine like terms. 3r^2 + 6r - r - 2 = 3r^2 + (6r - r) - 2 = 3r^2 + 5r - 2

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Find the product. Simplify your answer. $\newline$ $(3r - 1)(r + 2)$

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Math Problems

Algebra 1

Multiply two binomials

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Q. Find the product. Simplify your answer.

\newline

(3r - 1)(r + 2)

Apply Distributive Property: Apply the distributive property to multiply the two binomials. $\newline$ $(3r - 1)(r + 2) = 3r(r + 2) - 1(r + 2)$
Distribute $3r$ : Distribute $3r$ to both terms in the second binomial. $\newline$ 3r(r + 2) = 3r \times r + 3r \times 2$\newline= 3r^2 + 6r$
Distribute $-1$ : Distribute $-1$ to both terms in the second binomial. $\newline$ -1(r + 2) = -1 \times r - 1 \times 2$\newline= -r - 2$
Combine Results: Combine the results from Step $2$ and Step $3$ . $\newline$ $(3r - 1)(r + 2) = 3r^2 + 6r - r - 2$
Combine Like Terms: Combine like terms. $\newline$ $3r^2 + 6r - r - 2 = 3r^2 + (6r - r) - 2$ $\newline$ $= 3r^2 + 5r - 2$