Find the product. Simplify your answer. (3n - 2)(3n + 2) ______

Identify Special Case: Identify the special case that applies here. (3n - 2)(3n + 2) is in the form of (a - b)(a + b). Special case: (a - b)(a + b) = a^2 - b^2Identify Values of a and b: Identify the values of a and b. Compare (3n - 2)(3n + 2) with (a - b)(a + b). a = 3n b = 2Apply Difference of Squares: Apply the difference of squares to expand (3n - 2)(3n + 2). (a - b)(a + b) = a^2 - b^2 (3n - 2)(3n + 2) = (3n)^2 - (2)^2Simplify Expression: Simplify (3n)^2 - (2)^2. (3n)^2 - (2)^2 = (3n * 3n) - (2 * 2) = 9n^2 - 4

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Find the product. Simplify your answer. $\newline$ $(3n - 2)(3n + 2)$

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Math Problems

Algebra 1

Multiply two binomials: special cases

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Q. Find the product. Simplify your answer.

\newline

(3n - 2)(3n + 2)

Identify Special Case: Identify the special case that applies here. $\newline$ $(3n - 2)(3n + 2)$ is in the form of $(a - b)(a + b)$ . $\newline$ Special case: $(a - b)(a + b) = a^2 - b^2$
Identify Values of $a$ and $b$ : Identify the values of $a$ and $b$ . Compare $(3n - 2)(3n + 2)$ with $(a - b)(a + b)$ . $a = 3n$ $b = 2$
Apply Difference of Squares: Apply the difference of squares to expand $(3n - 2)(3n + 2)$ . $\newline$ $(a - b)(a + b) = a^2 - b^2$ $\newline$ $(3n - 2)(3n + 2) = (3n)^2 - (2)^2$
Simplify Expression: Simplify $(3n)^2 - (2)^2.$ $(3n)^2 - (2)^2 = (3n \times 3n) - (2 \times 2)$ $= 9n^2 - 4$